If \(2^{y-4} \times 6^{y-4} = 12^{-4}\), then the value of \(2y - 8\) is:
-8
Since \(2 \times 6 = 12\), the left side can be written as \((2 \times 6)^{y-4} = 12^{y-4}\).
Comparing \(12^{y-4} = 12^{-4}\), the exponents must be equal, so \(y - 4 = -4\), giving \(y = 0\).
Substituting, \(2y - 8 = 2(0) - 8 = -8\).
Hence, the value of \(2y - 8\) is \(-8\).
Important Questions from Algebra
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).
