Three impedances, each of (3−4j) Ω, are connected in delta to a 200 V, three-phase, 50 Hz balanced supply. What are the values of line current and phase current, respectively, in the delta-connected load?
$ 40 \sqrt3 A and 40 A$
To find the line current and phase current in a delta-connected load, we first need to understand the relationship between line current, phase current, and the impedance in a delta connection.
Step-by-Step Solution:
- The given impedance for each phase in the delta is (3 - 4j)\, \Omega.
- First, calculate the magnitude of the phase impedance: |Z| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\, \Omega.
- Given the line voltage across the delta connection is 200 V, the phase voltage is the same as the line voltage in a delta connection. Therefore: V_{phase} = 200\, V.
- Calculate the phase current using Ohm's Law, I_{phase} = \frac{V_{phase}}{|Z|}: I_{phase} = \frac{200}{5} = 40\, A.
- In a delta-connected system, the line current I_{line} is related to the phase current I_{phase} by: I_{line} = \sqrt{3} \times I_{phase}.
- Therefore, the line current is: I_{line} = \sqrt{3} \times 40 = 40 \sqrt{3}\, A.
- Hence, the values of the line current and phase current in the delta-connected load are 40√3 A and 40 A, respectively.
Conclusion:
The correct answer is: 40 \sqrt{3} A (line current) and 40 A (phase current).
Similar Questions
For supplying a large three-phase load with neutral connection requirement, which transformer connection is generally preferred?
Important Questions from Three Phase Transformer Basics
A three-phase, three winding Δ/Δ/Y (1.1 kV/6.6 kV/400 V) transformer is energized from AC mains at the 1.1 kV side. It supplies 900 kVA load at 0.8 power factor lag from the 6.6 kV winding and 300 kVA load at 0.6 power factor lag from the 400 V winding. The RMS line current in ampere drawn by the 1.1 kV winding from the mains is ___________. (Give the answer up to one decimal place.)
The core of a three-phase, 50 Hz, 1000/400 V delta/star: 300 kVA core type transformer operated with a flux of 0.04 wb. Find the EMF per turn.
A three-phase transformer has 600 primary turns and 200 secondary turns. If the supply voltage is 1000 V, find the secondary line voltage on no-load when the windings are connected in star–delta.
In Three Phase Transformer, The load Current is 139.1 A, and Secondary Voltage is 415 V. The Rating of the Transformer would be:
If the primary line voltage rating is 3.3 kV (Y side) of a 25 kVA, Y-Δ transformer (the per phase turns ratio is 5: 1), then the line current rating of the secondary side (in Ampere) is _________.
