This problem involves calculating time based on simple interest principles. We need to find how long it takes for an initial sum of money to become three times its original value.
Let the principal sum be P.
For simple interest, the interest earned is directly proportional to the time period, provided the principal and rate remain constant. We can write this relationship as:
$ \frac{SI_1}{T_1} = \frac{SI_2}{T_2} $Substitute the values from our two scenarios:
$ \frac{P}{\frac{13}{3}} = \frac{2P}{T_2} $Now, solve for T2. First, cancel P from both sides:
$ \frac{1}{\frac{13}{3}} = \frac{2}{T_2} $Simplify the left side:
$ \frac{3}{13} = \frac{2}{T_2} $Cross-multiply to find T2:
$ T_2 = 2 \times \frac{13}{3} $ $ T_2 = \frac{26}{3} \text{ years} $Convert the improper fraction to a mixed number:
$ T_2 = 8 \frac{2}{3} \text{ years} $This matches the time required for the sum to triple itself.
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If the interest on a sum of Rs.1200 is more than the interest on Rs.1000 by Rs.120 in three years, then what is the rate of interest per annum?.
The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?
A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?