This problem requires calculating the total marks for an examination using information about a student's score and the passing criteria.
The student received 70 marks and fell short of the passing score by 20 marks. To find the minimum marks required to pass the examination, we add the marks scored to the shortfall.
Passing Marks = Marks Scored + Marks Shortage
Passing Marks = $70 + 20 = 90$ marks.
We are given that 40% of the total marks are needed to pass. We have calculated that the passing marks are 90.
Let the Maximum Marks be represented by $M$. The relationship can be written as:
$40\% \text{ of } M = 90$
To solve for $M$, we convert the percentage to a fraction and set up the equation:
$\frac{40}{100} \times M = 90$
Now, isolate $M$ to find the maximum marks:
$M = \frac{90 \times 100}{40}$
$M = \frac{9000}{40}$
Simplify the fraction:
$M = \frac{900}{4}$
$M = 225$
Thus, the maximum marks for the examination is 225.
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