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Question

A student must score 40% marks to pass an examination. He gets 70 marks and fails by 20 marks. Find the maximum marks.

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
225

Maximum Marks Calculation: Examination Scoring

This problem requires calculating the total marks for an examination using information about a student's score and the passing criteria.

Determine Passing Marks

The student received 70 marks and fell short of the passing score by 20 marks. To find the minimum marks required to pass the examination, we add the marks scored to the shortfall.

Passing Marks = Marks Scored + Marks Shortage

Passing Marks = $70 + 20 = 90$ marks.

Calculate Maximum Marks

We are given that 40% of the total marks are needed to pass. We have calculated that the passing marks are 90.

Let the Maximum Marks be represented by $M$. The relationship can be written as:

$40\% \text{ of } M = 90$

To solve for $M$, we convert the percentage to a fraction and set up the equation:

$\frac{40}{100} \times M = 90$

Now, isolate $M$ to find the maximum marks:

$M = \frac{90 \times 100}{40}$

$M = \frac{9000}{40}$

Simplify the fraction:

$M = \frac{900}{4}$

$M = 225$

Thus, the maximum marks for the examination is 225.

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Important Questions from Percentage

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