This problem involves finding the original amount when a percentage of it and the corresponding value are known.
We can express the given information as an equation:
$6.25\% \times A = ₹75$
To find the total amount $A$, we first convert the percentage to a decimal or a fraction.
As a decimal: $6.25\% = \frac{6.25}{100} = 0.0625$.
The equation becomes:
$0.0625 \times A = 75$
Now, we solve for $A$ by dividing the expenditure by the decimal percentage:
$A = \frac{75}{0.0625}$
Alternatively, we can convert $6.25\%$ to a fraction:
$6.25\% = \frac{6.25}{100} = \frac{625}{10000} = \frac{1}{16}$
The equation is:
$\frac{1}{16} \times A = 75$
Solving for $A$:
$A = 75 \times 16$
Performing the multiplication:
$A = 75 \times 16 = 1200$
Therefore, Rani had ₹1200.
In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?
What is the value of 9% of 5500 + 2.4% of 1100 - 40% of 1600?
Population of a village is 7960 in which 4660 are female. If in that village 60% are literate in which 70% female are literate, then what is the number of literate male ?
The numbers of students of three classes of a school are in the ratio 4 : 5 : 6. If numbers of students in these classes increase by 25%, 20% and 25% respectively, then ratio of numbers of students will become:
In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;