Let the total amount be represented by '$A$'. The problem states that 60% of 40% of 32% of this amount is equal to ₹432.
We can write this relationship as a mathematical equation:
$ 60\% \times 40\% \times 32\% \times A = 432 $
First, convert the percentages to their decimal forms:
Substitute these decimal values back into the equation:
$ 0.60 \times 0.40 \times 0.32 \times A = 432 $
Now, multiply the decimal coefficients:
$ (0.60 \times 0.40) \times 0.32 \times A = 432 $
$ 0.24 \times 0.32 \times A = 432 $
$ 0.0768 \times A = 432 $
To find the amount '$A$', divide ₹432 by the combined decimal value (0.0768):
$ A = \frac{432}{0.0768} $
To simplify the division, we can multiply the numerator and the denominator by 10000 to remove the decimal:
$ A = \frac{432 \times 10000}{0.0768 \times 10000} = \frac{4320000}{768} $
Perform the division:
$ A = 5625 $
Therefore, the total amount is ₹5,625.
Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;
The income of A is 45% more than the income of B and the income of C is 60% less than the sum of the incomes of A and B. The income of D is 20% more than that of C. If the difference between the incomes of B and D is Rs. 13200, then the income (in Rs.) of C is:
The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget.
The population of a city increased by 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then population 2 years ago was:
The income of A is 30% less than the income of B and the income of B is 137.5% more than that of C. If the income of A is Rs. 28500 less than that of B, then the income (in Rs.) of C is: