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Question

$60\%$ of $40\%$ of $32\%$ of an amount is ₹432. What is the amount (in ₹)?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
5,625

Amount Calculation Using Percentages

Let the total amount be represented by '$A$'. The problem states that 60% of 40% of 32% of this amount is equal to ₹432.

We can write this relationship as a mathematical equation:

$ 60\% \times 40\% \times 32\% \times A = 432 $

First, convert the percentages to their decimal forms:

  • $60\% = \frac{60}{100} = 0.60$
  • $40\% = \frac{40}{100} = 0.40$
  • $32\% = \frac{32}{100} = 0.32$

Substitute these decimal values back into the equation:

$ 0.60 \times 0.40 \times 0.32 \times A = 432 $

Now, multiply the decimal coefficients:

$ (0.60 \times 0.40) \times 0.32 \times A = 432 $

$ 0.24 \times 0.32 \times A = 432 $

$ 0.0768 \times A = 432 $

To find the amount '$A$', divide ₹432 by the combined decimal value (0.0768):

$ A = \frac{432}{0.0768} $

To simplify the division, we can multiply the numerator and the denominator by 10000 to remove the decimal:

$ A = \frac{432 \times 10000}{0.0768 \times 10000} = \frac{4320000}{768} $

Perform the division:

$ A = 5625 $

Therefore, the total amount is ₹5,625.

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Important Questions from Percentage

  1. In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?

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  4. The numbers of students of three classes of a school are in the ratio 4 : 5 : 6. If numbers of students in these classes increase by 25%, 20% and 25% respectively, then ratio of numbers of students will become:

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