To determine by what percentage Meena's income is less than Richa's income, we need to apply the concept of percentage change. Let's solve the problem step-by-step:
- Let's assume Meena's income is \(M\).
- Richa's income is given to be \(9\frac{1}{11}\%\) more than Meena's income. This can be expressed as: \(R = M + \frac{101}{110}M = \frac{121}{110}M\), because \(9\frac{1}{11}\%\) is equivalent to the fraction \(\frac{101}{110}\).
- Therefore, the income of Richa, \(R\), is \(\frac{121}{110}M\).
- Now, we need to find by what percentage Meena's income is less than Richa's income.
- The difference in income can be calculated as: \(R - M = \frac{121}{110}M - M = \left(\frac{121}{110} - 1\right)M = \frac{11}{110}M\).
- The percentage difference with respect to Richa's income is: \(\left(\frac{\frac{11}{110}M}{\frac{121}{110}M}\right) \times 100\%\) which simplifies to \(\left(\frac{11}{121}\right) \times 100\% = \frac{1100}{121}\%\).
- Calculating the percentage: \(\frac{1100}{121} \approx 9.0909\%\), which is simplified to approximately \(9.0909\%\) or \(8\frac{4}{12}\%\).
Therefore, the correct option is \(8\frac{4}{12}\%\).
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Important Questions from Percentage
In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?
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Population of a village is 7960 in which 4660 are female. If in that village 60% are literate in which 70% female are literate, then what is the number of literate male ?
The numbers of students of three classes of a school are in the ratio 4 : 5 : 6. If numbers of students in these classes increase by 25%, 20% and 25% respectively, then ratio of numbers of students will become:
In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;
