This problem asks us to find the initial number of apples a fruit seller had, given the percentage he sold and the number remaining.
We can solve this step-by-step:
If the seller sold 40% of his apples, the percentage he still has left is the total percentage (100%) minus the percentage sold.
Remaining Percentage = \(100\% - 40\% = 60\%\)
This means the 240 apples he has left represent 60% of his original stock.
Let '\(T\)' represent the total number of apples the fruit seller originally had.
We know that 60% of the total apples (\(T\)) is equal to 240.
We can write this as an equation:
\(60\% \times T = 240\)
To make calculations easier, let's convert the percentage to a decimal:
\(60\% = \frac{60}{100} = 0.60\)
So the equation becomes:
\(0.60 \times T = 240\)
To find '\(T\)', we need to isolate it by dividing both sides of the equation by 0.60:
\(T = \frac{240}{0.60}\)
To perform the division, we can multiply the numerator and denominator by 100 to remove the decimal:
\(T = \frac{240 \times 100}{0.60 \times 100} = \frac{24000}{60}\)
Now, simplify the fraction:
\(T = \frac{2400}{6}\)
\(T = 400\)
Therefore, the fruit seller originally had 400 apples.
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