A store sells pens and notebooks. If 3 pens and 2 notebooks cost ₹120, and 2 pens and 4 notebooks cost ₹140, what is the price of one notebook?
₹22.50
Let the price of one pen be \(p\) and one notebook be \(n\).
Form the two equations: \(3p + 2n = 120\) and \(2p + 4n = 140\).
Multiply the first equation by 2: \(6p + 4n = 240\).
Subtract the second equation from this: \((6p + 4n) - (2p + 4n) = 240 - 140\), giving \(4p = 100\), so \(p = 25\).
Substitute \(p = 25\) into \(3p + 2n = 120\): \(75 + 2n = 120\), so \(2n = 45\) and \(n = 22.5\).
Hence, the price of one notebook is ₹22.50.
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Important Questions from Algebra
The difference between the two positive numbers x and y where x > y, is 25% of x. If the value of y is 15, then the value of x is:
If p2 + q2 - r2 = 0, then the value of (p6 + q6 - r6) ÷ p2q2r2 is:
If √2 + √x = √3, then the value of x is equal to:
The sum of two numbers is 20 and their difference is 2.5. Ratio of these numbers will be:
If \(\rm \frac{\sqrt{19 - x \sqrt{12}}}{1} = \sqrt 4 - \sqrt 3\) then the value of x is equal to:
