A store sells pens and notebooks. If 3 pens and 2 notebooks cost ₹120, and 2 pens and 4 notebooks cost ₹140, what is the price of one notebook?
₹22.50
Let the price of one pen be \(p\) and one notebook be \(n\).
Form the two equations: \(3p + 2n = 120\) and \(2p + 4n = 140\).
Multiply the first equation by 2: \(6p + 4n = 240\).
Subtract the second equation from this: \((6p + 4n) - (2p + 4n) = 240 - 140\), giving \(4p = 100\), so \(p = 25\).
Substitute \(p = 25\) into \(3p + 2n = 120\): \(75 + 2n = 120\), so \(2n = 45\) and \(n = 22.5\).
Hence, the price of one notebook is ₹22.50.
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