The image will remain unchanged.
The question relates to the concept of light reflection and optics, specifically about how light behaves when passing through media of different refractive indices.
- The periscope utilizes two plane mirrors to redirect light, allowing the observer to see over obstacles. Normally, mirrors in a periscope are set at an angle of \(45^{\circ}\).
- In this scenario, the tube of the periscope is filled with a transparent liquid with a refractive index of \(1.5\). This means light traveling through the liquid will experience refraction but will not change its path when it reflects off the mirrors.
- The refractive index has no effect on the brightness or lateral position of the image as perceived through the periscope. The properties of the reflected light (such as intensity and direction) depend only on the reflective surfaces of the mirrors, not on the medium between them.
- Let's evaluate the options:
- The image will appear \(1.5\) times darker: This option is incorrect because the refractive index does not directly affect the brightness or intensity of the reflected light from the mirrors.
- The image will appear laterally shifted: This is incorrect because a lateral shift would imply the image has moved sideways, which is not affected by a change in the medium.
- The image will appear \(1.5\) times brighter: Again, this is incorrect because the medium’s refractive index does not change the brightness of the mirror-reflected image.
- The image will remain unchanged: This is correct. In terms of appearance, the image will be unaffected by the refractive index change since reflection on plane mirrors does not depend on the medium but rather on the mirrors themselves.
- Therefore, the correct interpretation is that the image will remain unchanged.
Similar Questions
Statement I: Due to diffused or irregular reflection of light, a closed room gets light even if no direct sunlight falls inside the room.
Statement II: Irregular reflection, where the reflected rays are not parallel, does not follow the laws of reflection.Myopia is a defect in human vision where an image of a
Human eye can see objects at different distances with contrasting illuminations. This is due to
A glass slab of refractive index \(1\cdot5\) is cut in the shape of a parallelepiped \(ABCD\) as shown in the figure. Surface \(BC\) is polished to form a perfect reflector. Light is incident at surface \(AB\) from inside at an angle \(\pi/3\). Which one of the following is the correct angle \(ABC\) (\(\theta\)) such that the reflected light retraces its path?
- Bottom of a tank containing water appears to be raised. It is due to
The part of the human eye on which the image is formed is
Colour vision in human eyes is the function of photoreceptor cells named
Ramesh cannot see distinctly objects kept beyond 2 m. This defect can be corrected by using a lens of power
Cornea in human eye
Light enters the eye through a thin membrane called
Important Questions from Reflection and Refraction
Which of the following statement is correct?
I. Refraction is due to the change in the speed of light when it enters from one transparent medium to another.
II. The refractive index of water is 1.33.
The focal length of the eye lens increases when eye muscles:
Myopia is also known as ______.
Part of the eye which controls the light entering, is called as
Which defect of vision is corrected using cylindrical lenses in spectacles ?
