A city is planning a new park in the shape of a regular hexagon with each side measuring 10 meters. Which of the following is closest to the area of the park?
259.8 square meters
Area of a regular hexagon with side s: \(\dfrac{3\sqrt3}{2}s^2\).
With s=10: \(\dfrac{3\sqrt3}{2}\times100 = 150\sqrt3 \approx 259.8\) sq metres.
Hence, the closest area of the park is 259.8 square metres.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)