Which of the following statements are true for SCR ? (a) UJT is a phase controlling device for SCR rectifier. (b) The average load voltage of SCR rectifier is greater than average load voltage of ordinary diode rectifier. (c) Power delivered to the load in SCR rectifier is maximum when SCR firing angle is zero degree. (d) SCR can control the amount of power fed to the load by switching current OFF and ON upto many thousand times a second.
(a), (c) and (d) are correct
(a) — UJT as the phase-control device ✓. A unijunction transistor in a relaxation oscillator is the classic SCR trigger circuit: a capacitor charges through a variable resistor until it reaches the UJT's peak-point voltage \(V_P=\eta V_{BB}+V_D\), at which point the UJT fires and dumps a sharp pulse into the SCR gate. Adjusting the RC time constant moves the firing instant within each half cycle — that is exactly phase control, and the pulse is naturally short, which suits gate drive.
(c) — maximum power at zero firing angle ✓. For a half-wave controlled rectifier
\(V_{dc}=\dfrac{V_m}{2\pi}(1+\cos\alpha)\)
which is largest at α = 0 and falls to zero at α = 180°. Firing at zero delay makes the SCR conduct for the whole available half cycle, so it behaves like an ordinary diode and delivers maximum power.
(d) — on/off switching thousands of times a second ✓. An SCR fires once per cycle of the supply, so on a 50 Hz mains it switches 50–100 times a second; in inverter and chopper circuits with forced commutation the switching rate reaches many kilohertz. Control by switching rather than by dropping voltage across a series element is what makes thyristor control so efficient — the device is either fully on or fully off, so it dissipates very little.
(b) — SCR rectifier gives a greater average voltage than a diode rectifier ✗. Exactly the reverse. The whole purpose of the firing angle is to delay conduction, so part of each half cycle is lost. The best an SCR can do is α = 0, where it merely equals the diode; for every α > 0 the average output is lower. This is the statement the question turns on.
So the true statements are (a), (c) and (d) — option 2.
Hence, the correct answer is (a), (c) and (d).
In two transistor model of an SCR the expression for anode current is given by:

Match the following lists :
| List - I | List - II |
| a. SCR can be turned off by | i. it turns off when anode current falls below this value. |
| b. Turn on time of SCR can be reduced by | ii. the rectangular pulse of high amplitude and narrow width |
| c. Holding current for an SCR means | iii. its anode current interruption |
| d. A forward current can be applied to an SCR after | iv. its gate recovery time |
Correct Codes are :
The voltage safety factor (Vf) of a thyristor is given by :
In SCR, the following statements are given :
(a) It acts as a short circuit device.
(b) It acts as an open circuit device.
(c) ON state voltage is approximately 2-5 Volts.
(d) ON state voltage is approximately 50-100 Volts.
Which of the above statements are correct ?
An SCR is turned off by :
For a two transistor model, the value of α1 + α2 is equal to :
_______ is the device which acts like an N-P-N and a P-N-P transistor connected base-to-base and emitter-to-collector.
SCR stands for
A conducting SCR can be opened by reducing __________to zero.
Which of the following statements correctly describes the structure of a Silicon Controlled Rectifier (SCR)?
The thyristors which have a turn-off time less than _________ are called inverter grade thyristors.