Which of the following letter-clusters can replace the question mark (?) In the given series to make it logically complete? DNU, ?, NXE, SCJ, XHO
ISZ
We are given a series of letter clusters: DNU, ?, NXE, SCJ, XHO. To find the missing cluster, we need to identify the pattern or rule that connects the clusters in the series. We can analyse the progression of each letter position independently.
Let's look at the first letter of each cluster:
Let's look at the difference in their alphabetical positions:
The differences are 10, 5, 5. It appears the pattern might be adding 5 to the position of the previous letter, except for the first step. Let's assume the pattern is consistent (+5). To find the first letter of the missing cluster, we add 5 to the position of the first letter of DNU:
First letter position = Position of D + 5 = \(4 + 5 = 9\)
The 9th letter in the alphabet is I.
Let's check if this fits the rest of the series: I (9) + 5 = N (14), N (14) + 5 = S (19), S (19) + 5 = X (24). This confirms the pattern of adding 5 to the first letter's position.
Now, let's look at the second letter of each cluster:
Let's look at the difference in their alphabetical positions, considering the alphabet wraps around (A=1, Z=26, then A=1, etc.):
Again, the pattern appears to be adding 5 to the position of the previous letter, except for the first step difference being 10. Assuming the pattern is consistent (+5) throughout:
Second letter position = Position of N + 5 = \(14 + 5 = 19\)
The 19th letter in the alphabet is S.
Let's check if this fits: S (19) + 5 = X (24), X (24) + 5 = C (3) (24+5 = 29; 29 - 26 = 3), C (3) + 5 = H (8). This pattern of adding 5 (with wrap-around) works for the second letter.
Finally, let's look at the third letter of each cluster:
Let's look at the difference in their alphabetical positions, considering the wrap-around:
Once again, the pattern is adding 5 to the position of the previous letter, with wrap-around. Applying this pattern to find the third letter of the missing cluster:
Third letter position = Position of U + 5 = \(21 + 5 = 26\)
The 26th letter in the alphabet is Z.
Let's check if this fits: Z (26) + 5 = E (5) (26+5 = 31; 31 - 26 = 5), E (5) + 5 = J (10), J (10) + 5 = O (15). This pattern of adding 5 (with wrap-around) works for the third letter.
Combining the letters found for each position:
The missing letter cluster is ISZ.
Each letter position in the cluster follows an independent pattern where its alphabetical position increases by 5 compared to the corresponding letter in the previous cluster. The alphabet wraps around from Z back to A.
| Cluster | 1st Letter (Position) | 2nd Letter (Position) | 3rd Letter (Position) |
|---|---|---|---|
| DNU | D (4) | N (14) | U (21) |
| ISZ | I (9) \(4+5\) | S (19) \(14+5\) | Z (26) \(21+5\) |
| NXE | N (14) \(9+5\) | X (24) \(19+5\) | E (5) \(26+5=31 \equiv 5\) |
| SCJ | S (19) \(14+5\) | C (3) \(24+5=29 \equiv 3\) | J (10) \(5+5\) |
| XHO | X (24) \(19+5\) | H (8) \(3+5\) | O (15) \(10+5\) |
The cluster that logically completes the series is ISZ.
| Letter Position | Pattern | Example (1st to 2nd) |
|---|---|---|
| 1st Letter | Add 5 to previous letter's position (wrap-around A-Z) | D(4) + 5 = I(9) |
| 2nd Letter | Add 5 to previous letter's position (wrap-around A-Z) | N(14) + 5 = S(19) |
| 3rd Letter | Add 5 to previous letter's position (wrap-around A-Z) | U(21) + 5 = Z(26) |
Letter series questions are common in reasoning tests and involve finding a pattern in a sequence of letters or letter clusters. Common patterns include:
To solve these problems, it's helpful to know the alphabetical position of each letter and systematically check for patterns across the series, usually focusing on the first letter, then the second, and so on.
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