Which of the following equations represents a line parallel to \(3x - 2y = 6\)?
\(3x - 2y = 10\)
Two straight lines are parallel exactly when they have equal slopes.
Writing a line as \(ax + by = c\), its slope is \(-\dfrac{a}{b}\) (rearranging to \(y = -\tfrac{a}{b}x + \tfrac{c}{b}\)).
For the given line \(3x - 2y = 6\): \(a = 3,\ b = -2\), so slope \(= -\dfrac{3}{-2} = \dfrac{3}{2}\).
A parallel line keeps the same \(x\) and \(y\) coefficients; only the constant on the right may differ.
The option \(3x - 2y = 10\) has slope \(-\dfrac{3}{-2} = \dfrac{3}{2}\), identical to the given line, so the two are parallel (and not the same line, since the constant differs).
Key idea: same coefficient ratio \(a:b\) means same slope. The required equation is \(3x - 2y = 10\).
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