A drone flies along \(y = -x + 10\). Another follows \(y = x - 4\). At what point do they intersect?
(7,3)
The two drone paths are straight lines \(y = -x + 10\) and \(y = x - 4\). Their meeting point is the point that satisfies both equations at once.
At the intersection the two expressions for \(y\) must be equal, so we set them equal to each other.
\(-x + 10 = x - 4\)
Bring the variable terms together: \(10 + 4 = x + x\), which gives \(14 = 2x\).
Hence \(x = 7\).
Substitute \(x = 7\) into \(y = x - 4\): \(y = 7 - 4 = 3\).
Check in the first line: \(y = -7 + 10 = 3\), which matches, so the point is consistent.
Therefore the two drones meet at the point (7, 3).
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Important Questions from Co-ordinate Geometry
In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
The area (in sq. units) of the triangle formed by the graphs of 8x + 3y = 24, 2x + 8 = y and the x-axis is:
In which quadrant both abscissa and ordinate are negative?
Find the slope of the line joining the points (3, -4) and (5, 2).
Find the value of K for which equation x – Ky = 2, 3x + 2y = 5 has unique solution.
