The equation of a line is \(2x-3y=6\). What is the slope of the line?
\(\dfrac{2}{3}\)
Given: the line \(2x-3y=6\), and we need its slope.
The slope-intercept form of a line is \(y=mx+c\), where \(m\) is the slope.
Rearrange the equation to isolate \(y\): \(2x-3y=6\Rightarrow -3y=6-2x\).
Divide throughout by \(-3\): \(y=\dfrac{6-2x}{-3}=\dfrac{2x-6}{3}\).
This gives \(y=\dfrac{2}{3}x-2\), so the coefficient of \(x\) is the slope.
Therefore the slope \(m=\dfrac{2}{3}\).
Hence the slope of the line is \(\mathbf{\dfrac{2}{3}}\), i.e. 2/3.
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