A triangle has vertices with coordinates A(1,2), B(5,2), and C(3,8). What is the y-coordinate of its centroid?
4
Given the three vertices \(A(1,2),\ B(5,2),\ C(3,8)\), we need the y-coordinate of the centroid.
The centroid of a triangle is the average of the coordinates of its three vertices.
Its y-coordinate is given by \(y = \dfrac{y_{1} + y_{2} + y_{3}}{3}\).
Here \(y_{1}=2,\ y_{2}=2,\ y_{3}=8\).
So \(y = \dfrac{2 + 2 + 8}{3}\).
\(y = \dfrac{12}{3} = 4\).
Hence the y-coordinate of the centroid is 4.
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In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
In which quadrant both abscissa and ordinate are negative?
Find the slope of the line joining the points (3, -4) and (5, 2).
A1 (x1, y1), A2 (x2, y2), A3 (x3, y3) and A4 (x4, y4) are 4 points, p1 divides A1A2 in the ratio 1 ∶ 1, p2 divides P1A3 in the ratio 1 ∶ 2, P3 divides p2A4 in the ratio 1 ∶ 3. Then the coordinates of p3 are:
If (3, 2) are coordinates of the centroid of a triangle, whose vertices are (0, 4), (-2, 0) and (p, 2), then find the value of p.
