In which quadrant both abscissa and ordinate are negative?
Third
The question asks us to identify the specific quadrant in the Cartesian coordinate system where both the abscissa (which is the x-coordinate) and the ordinate (which is the y-coordinate) have negative values.
In a coordinate plane:
The Cartesian plane is divided into four quadrants by the x-axis (horizontal) and the y-axis (vertical).
We are looking for the quadrant where both the abscissa and the ordinate are negative. Based on the definitions above:
Therefore, the quadrant where both the abscissa and the ordinate are negative is the Third quadrant.
| Quadrant | Abscissa (x) | Ordinate (y) |
|---|---|---|
| I | + | + |
| II | - | + |
| III | - | - |
| IV | + | - |
This confirms that the Third quadrant is the correct location for points with negative abscissa and negative ordinate values.
The graphs of the linear equations 4x - 2y = 10 and 4x + ky = 2 intersect at a point (a, 4). The value of k is equal to:
In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
The area (in sq. units) of the triangle formed by the graphs of 8x + 3y = 24, 2x + 8 = y and the x-axis is:
Find the slope of the line joining the points (3, -4) and (5, 2).
Find the value of K for which equation x – Ky = 2, 3x + 2y = 5 has unique solution.