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Question

The coordinates of the vertices of a triangle are \(A(0,0),\ B(8,0),\) and \(C(0,6)\). What is the location of the orthocenter?

This question was previously asked in
SSC CHSL 2025 Tier 1 Question Paper (21-Nov-2025) (Shift 1)
The correct answer is

\((0,0)\)

The vertices are \(A(0,0)\), \(B(8,0)\) and \(C(0,6)\). Side \(AB\) lies along the x-axis (both points have \(y=0\)) and side \(AC\) lies along the y-axis (both points have \(x=0\)).

The x-axis and y-axis meet at right angles, so \(AB\perp AC\). The triangle is therefore right-angled, with the right angle at vertex \(A(0,0)\).

The orthocentre is the common point of the three altitudes, where each altitude is the line drawn from a vertex perpendicular to the opposite side.

Consider the altitude from \(C\) to side \(AB\). Since \(AC\) is already perpendicular to \(AB\), the leg \(CA\) itself is that altitude, and it passes through \(A\).

Likewise the altitude from \(B\) to side \(AC\) is the leg \(BA\), which also passes through \(A\). Two altitudes already meet at \(A\), so the third must pass through \(A\) as well.

This illustrates the general property: in any right-angled triangle the orthocentre coincides with the vertex holding the right angle.

Hence the orthocentre is at \((0,0)\).

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Important Questions from Co-ordinate Geometry

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