The task is to determine which group of letters has a sum of alphabetical positions equal to 29. We use the standard numbering where A=1, B=2, ..., Z=26.
We calculate the sum for each option:
| Group | Letters | Positions | Sum |
| 1 | P, Q, R | 16, 17, 18 | $16 + 17 + 18 = 51$ |
| 2 | C, D, Y | 3, 4, 25 | $3 + 4 + 25 = 32$ |
| 3 | A, B, Z | 1, 2, 26 | $1 + 2 + 26 = 29$ |
| 4 | M, N, O | 13, 14, 15 | $13 + 14 + 15 = 42$ |
The group A, B, Z yields a sum of 29.
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