When one object reference variable is assigned to another object reference variable then
a copy of the reference is created.
In Java, a variable of a class type does not hold the object itself; it holds a reference (an address-like handle) to an object stored on the heap.
For Box b1 = new Box(); Box b2 = b1; the assignment copies the value stored in b1, which is the reference. Now b1 and b2 refer to the same single object, so a change made through b2 is visible through b1.
No new object is created; copying an object needs an explicit operation such as clone() or a copy constructor. Saying no reference copy is made is wrong, because b2 holds its own copy of the reference value. The assignment is perfectly legal whenever the types are compatible.
a copy of the reference is created. option is correct.
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Consider the following JAVA program :
public class First {
public static int CBSE (int x) {
if (x < 100) x = CBSE (x + 10);
return (x – 1);
}
public static void main (String[] args){
System.out.print(First.CBSE(60));
}
}
What does this program print ?
Given the array of integers ‘array’ shown below :
13 7 27 2 18 33 9 11 22 8 What is the output of the following JAVA statements ?
int [ ] p = new int [10];
int [ ] q = new int [10];
for (int k = 0; k < 10; k ++)
p[k] = array [k];
q = p;
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Important Questions from Java
Arrange the following applet life cycles methods in sequence
A. start()
B. paint()
C. init()
D. stop()
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Which of the following statement(s) is/are correct regarding java programming?
I. Place a semicolon immediately after a method header
II. Define a method outside the braces of a class definition
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