All Exams Test series for 1 year @ ₹349 only
Question

What would be the value of \(\cos(105^\circ)\)

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
$\frac{(1-\sqrt{3})}{2\sqrt{2}}$

Calculating Cosine 105 Degrees

To find the value of \(\cos(105^\circ)\), we break down \(105^\circ\) into the sum of two standard angles: \(105^\circ = 60^\circ + 45^\circ\). This allows us to use trigonometric identities.

Applying the Cosine Sum Identity

The angle addition identity for cosine states: \(\cos(A + B) = \cos A \cos B - \sin A \sin B\)

Applying this identity with \(A = 60^\circ\) and \(B = 45^\circ\): \(\cos(105^\circ) = \cos(60^\circ + 45^\circ) = \cos(60^\circ)\cos(45^\circ) - \sin(60^\circ)\sin(45^\circ)\)

Substituting Known Trigonometric Values

We use the known values for these standard angles:

  • \(\cos(60^\circ) = \frac{1}{2}\)
  • \(\sin(60^\circ) = \frac{\sqrt{3}}{2}\)
  • \(\cos(45^\circ) = \frac{\sqrt{2}}{2}\)
  • \(\sin(45^\circ) = \frac{\sqrt{2}}{2}\)

Performing the Calculation

Substitute these values into the expanded formula:

\(\cos(105^\circ) = \left(\frac{1}{2}\right) \left(\frac{\sqrt{2}}{2}\right) - \left(\frac{\sqrt{3}}{2}\right) \left(\frac{\sqrt{2}}{2}\right)\)

Simplify the terms:

\(\cos(105^\circ) = \frac{\sqrt{2}}{4} - \frac{\sqrt{6}}{4}\)

Combine the terms over the common denominator:

\(\cos(105^\circ) = \frac{\sqrt{2} - \sqrt{6}}{4}\)

Matching the Result Format

The calculated value is \(\frac{\sqrt{2} - \sqrt{6}}{4}\). Let's verify Option A: \(\frac{(1-\sqrt{3})}{2\sqrt{2}}\). To compare, we rationalize the denominator of Option A:

\(\frac{(1-\sqrt{3})}{2\sqrt{2}} = \frac{(1-\sqrt{3}) \times \sqrt{2}}{(2\sqrt{2}) \times \sqrt{2}} = \frac{\sqrt{2} - \sqrt{6}}{2 \times 2} = \frac{\sqrt{2} - \sqrt{6}}{4}\)

The calculated value matches Option A.

Was this answer helpful?

Similar Questions

  1. If \(\cos\theta = 24/25\) then \(\cot\theta\) will be
  2. Value of \(\sin 60^\circ / \cos 60^\circ\)
  3. In ΔPQR, ∠Q = 90°. If tan R = 1/2, then what is the value of (sec P(3cos R − sin P)) / (4cosec R (4sin R − cos P)) ?
  4. In a right angled triangle, right-angled at $A$, what is the value of $\sec B$, if $BC$ is 5.2cm and $AB$ is 3cm.
  5. Value of \(\sin 26^\circ / \cos 64^\circ\)

Important Questions from Trigonometric Ratios

  1. If $\sin\theta = \frac{p^2 - 1}{p^2 + 1}$, and $\theta$ is an acute angle, then find the value of $\cos\theta$.
  2. Let ABC be a right-angled triangle such that $\angle B = 90^\circ$, AB = 12 cm and AC = 13 cm. Find the value of $\tan A - \cot C$.
  3. What is \(\tan \alpha + \tan \beta\) equal to?

  4. If \(\cos\theta = 24/25\) then \(\cot\theta\) will be
  5. Value of \(\sin 60^\circ / \cos 60^\circ\)
Need Expert Advice?
Test Series
RRB ALP img
Railways
RRB ALP 2026 Mock Test series
1035 Tests 1 Tests Free
1734 Attempts
4.3(257)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App