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Question

Value of \(\sin 60^\circ / \cos 60^\circ\)

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
$\sqrt{3}$

Evaluating Trigonometric Ratios for 60 Degrees

The question asks for the value of the expression \(\frac{\sin 60^\circ}{\cos 60^\circ}\).

Using Trigonometric Identity

Recall the fundamental trigonometric identity:

\(\tan \theta = \frac{\sin \theta}{\cos \theta}\)

Applying this identity to the given expression with \(\theta = 60^\circ\):

\(\frac{\sin 60^\circ}{\cos 60^\circ} = \tan 60^\circ\)

Calculating the Value

We know the standard trigonometric values for \(60^\circ\):

  • \(\sin 60^\circ = \frac{\sqrt{3}}{2}\)
  • \(\cos 60^\circ = \frac{1}{2}\)

Substitute these values into the expression:

\(\frac{\sin 60^\circ}{\cos 60^\circ} = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}\)

To simplify the division of fractions, multiply the numerator by the reciprocal of the denominator:

\(\frac{\sqrt{3}}{2} \times \frac{2}{1} = \sqrt{3}\)

Alternatively, knowing that \(\tan 60^\circ = \sqrt{3}\) directly gives the answer.

Final Answer Determination

The calculated value is \(\sqrt{3}\). This corresponds to Option A.

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Important Questions from Trigonometric Ratios

  1. If \(cosec~\theta =\frac{29}{21}\) where 0 < θ < 90°, then what is the value of 4 sec θ + 4 tan θ?

  2. The value of \(\cot \left( {cose{c^{ - 1}}\frac{5}{3} + {{\tan }^{ - 1}}\frac{2}{3}\;} \right)\)

  3. The distance of the highest point on the graph of the function y = √3 cos x + sin x from the x-axis is:

  4. If A = π / 6 and B = π / 3, then consider the following statements:

    I. sin A + sin B = cos A + cos B

    II. tan A + tan B = cot A + cot B

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