To find the value of \(\cot\theta\) given \(\cos\theta = \frac{24}{25}\), we will use trigonometric identities and relationships. The formulae we will use are:
Step 1: Calculate \(\sin\theta\) using the Pythagorean identity:
Since we know that:
\(\cos\theta = \frac{24}{25}\)
We can substitute into \(\sin^2\theta + \cos^2\theta = 1\):
\(\sin^2\theta + \left(\frac{24}{25}\right)^2 = 1\)
\(\sin^2\theta + \frac{576}{625} = 1\)
\(\sin^2\theta = 1 - \frac{576}{625}\)
\(\sin^2\theta = \frac{625 - 576}{625}\)
\(\sin^2\theta = \frac{49}{625}\)
Taking the square root, since we assume \(\theta\) is in the first quadrant where \(\sin\theta\) is positive:
\(\sin\theta = \frac{7}{25}\)
Step 2: Calculate \(\cot\theta\) using the relation \(\cot\theta = \frac{\cos\theta}{\sin\theta}\):
\(\cot\theta = \frac{\frac{24}{25}}{\frac{7}{25}}\)
\(\cot\theta = \frac{24}{25} \times \frac{25}{7}\)
\(\cot\theta = \frac{24}{7}\)
Therefore, the value of \(\cot\theta\) is \(\frac{24}{7}\).
What is \(\tan \alpha + \tan \beta\) equal to?
If \(\cos x = \frac{5}{{13}}\) , x lies in the fourth quadrant, and determines the value of the other five trigonometric functions?