To find the value of \(\sec B\) in the given right-angled triangle, we need to first understand the trigonometric properties of the triangle.
In a right-angled triangle:
Given:
We need to find \(\sec B\), which is defined as:
\(\sec B = \frac{\text{Hypotenuse}}{\text{Adjacent side to } B} = \frac{BC}{AB}\)
Substituting the known values:
\(\sec B = \frac{5.2}{3}\)
Calculating this gives:
\(\sec B = 1.7333\ldots\)
Rounding this to two decimal places, we find:
\(\sec B \approx 1.73\)
Therefore, the correct answer is 1.73.
This calculation matches the option 1.73, confirming it is correct.
What is \(\tan \alpha + \tan \beta\) equal to?