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Question

In a right angled triangle, right-angled at $A$, what is the value of $\sec B$, if $BC$ is 5.2cm and $AB$ is 3cm.

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
1.73

To find the value of \(\sec B\) in the given right-angled triangle, we need to first understand the trigonometric properties of the triangle.

In a right-angled triangle:

  • The side opposite the right angle is the hypotenuse.
  • The sides forming the right angle are the adjacent and opposite sides, relative to the angle being considered.

Given:

  • The triangle is right-angled at \(A\).
  • \(BC = 5.2\, \text{cm}\) (this is the hypotenuse, since it is opposite the right angle at \(A\)).
  • \(AB = 3\, \text{cm}\) (this is one of the sides adjacent to angle \(B\)).

We need to find \(\sec B\), which is defined as:

\(\sec B = \frac{\text{Hypotenuse}}{\text{Adjacent side to } B} = \frac{BC}{AB}\)

Substituting the known values:

\(\sec B = \frac{5.2}{3}\)

Calculating this gives:

\(\sec B = 1.7333\ldots\)

Rounding this to two decimal places, we find:

\(\sec B \approx 1.73\)

Therefore, the correct answer is 1.73.

This calculation matches the option 1.73, confirming it is correct.

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