The question asks for the compound interest (CI) on a principal amount (P) of Rs. 25,000 over a time period (n) of 3 years at an annual interest rate (r) of 10%.
The formula to calculate the final amount (A) including compound interest is:
A = P \left(1 + \frac{r}{100}\right)^n
The compound interest (CI) is the difference between the final amount (A) and the principal (P):
CI = A - P \quad \text{or} \quad CI = P \left[ \left(1 + \frac{r}{100}\right)^n - 1 \right]
Substitute the given values into the formula:
P = 25,000
r = 10%
n = 3
Calculate the amount (A):
A = 25,000 \left(1 + \frac{10}{100}\right)^3
A = 25,000 \left(1 + 0.1\right)^3
A = 25,000 \left(1.1\right)^3
A = 25,000 \times 1.331
A = 33,275
Calculate the compound interest (CI):
CI = A - P
CI = 33,275 - 25,000
CI = 8,275
Therefore, the compound interest is Rs. 8,275.
A sum of money becomes three times itself in 3 years at compound interest.
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