This problem requires calculating the future value of an investment using the compound interest formula.
The formula for calculating the final amount (A) with compound interest is:
$ A = P \left(1 + \frac{r}{n}\right)^{nt} $
Where:
Substitute the given values into the formula:
$ A = 4500 \left(1 + \frac{0.10}{1}\right)^{1 \times 5} $
Simplify the expression:
$ A = 4500 (1 + 0.10)^5 $
$ A = 4500 (1.10)^5 $
Rounding the result to two decimal places, the amount to be paid at the end of 5 years is Rs. 7,247.30.
A sum of money becomes three times itself in 3 years at compound interest.
What is the rate of interest?
The certain sum amounts to Rs. 9,982.50 in \(2\frac{1}{2}\) years at 12% p.a., interest compounded 10-monthly. The sum (in Rs.) is:
The difference between the simple interest and the compound interest compounded annually on a certain sum of money for 2 years at a rate of 8% per annum is Rs. 16.80. Find the principle amount.
If a sum of ₹ 2000 is lent at 10% p.a. compound interest, what is the interest for the second year?
A sum becomes 5 times of itself in 3 years. at compound interest (interest is compounded annually). In how many years. will the sum becomes 125 times of itself?
If the compound interest on a certain sum of money for two years at 9% p.a. is Rs. 3,762, then the sum is: