The difference between the simple interest and the compound interest compounded annually on a certain sum of money for 2 years at a rate of 8% per annum is Rs. 16.80. Find the principle amount.
Rs. 2,625
The question asks us to find the principal amount given the difference between the simple interest (SI) and the compound interest (CI) for a specific time period and rate. We are given that the difference between CI and SI for 2 years at a rate of 8% per annum is Rs. 16.80. We need to determine the initial principal amount that was invested or borrowed.
Let's define the terms used in the problem:
The formula for Simple Interest (SI) is:
\(\text{SI} = \frac{P \times R \times T}{100}\)
For Compound Interest (CI), compounded annually, the amount (A) after T years is:
\(A = P \left(1 + \frac{R}{100}\right)^T\)
The Compound Interest (CI) itself is the amount minus the principal:
\(\text{CI} = A - P = P \left(1 + \frac{R}{100}\right)^T - P = P \left[ \left(1 + \frac{R}{100}\right)^T - 1 \right]\)
We are given the time period T = 2 years and the rate R = 8% per annum. The difference between CI and SI is Rs. 16.80.
Let's calculate SI for 2 years:
\(\text{SI} = \frac{P \times 8 \times 2}{100} = \frac{16P}{100} = \frac{4P}{25}\)
Now let's calculate CI for 2 years:
\(\text{CI} = P \left[ \left(1 + \frac{8}{100}\right)^2 - 1 \right]\)
\(\text{CI} = P \left[ \left(1 + \frac{2}{25}\right)^2 - 1 \right]\)
\(\text{CI} = P \left[ \left(\frac{27}{25}\right)^2 - 1 \right]\)
\(\text{CI} = P \left[ \frac{729}{625} - 1 \right]\)
\(\text{CI} = P \left[ \frac{729 - 625}{625} \right]\)
\(\text{CI} = P \left[ \frac{104}{625} \right]\)
The difference between CI and SI is:
\(\text{CI} - \text{SI} = \frac{104P}{625} - \frac{4P}{25}\)
To subtract these fractions, find a common denominator, which is 625:
\(\text{CI} - \text{SI} = \frac{104P}{625} - \frac{4P \times (625/25)}{625} = \frac{104P}{625} - \frac{4P \times 25}{625}\)
\(\text{CI} - \text{SI} = \frac{104P - 100P}{625} = \frac{4P}{625}\)
Alternatively, there is a direct formula for the difference between CI and SI for 2 years when interest is compounded annually:
\(\text{Difference} = P \left( \frac{R}{100} \right)^2\)
This formula is derived from the general expressions for CI and SI for 2 years. \(\text{CI} = P \left( \left(1 + \frac{R}{100}\right)^2 - 1 \right) = P \left( 1^2 + 2 \times 1 \times \frac{R}{100} + \left(\frac{R}{100}\right)^2 - 1 \right) = P \left( \frac{2R}{100} + \left(\frac{R}{100}\right)^2 \right)\) \(\text{SI} = \frac{P \times R \times 2}{100} = \frac{2PR}{100}\) \(\text{CI} - \text{SI} = P \left( \frac{2R}{100} + \left(\frac{R}{100}\right)^2 \right) - \frac{2PR}{100} = \frac{2PR}{100} + P\left(\frac{R}{100}\right)^2 - \frac{2PR}{100} = P\left(\frac{R}{100}\right)^2\)
Let's use this direct formula as it simplifies the calculation significantly.
We are given the difference is Rs. 16.80 and the rate R = 8%.
Using the formula: \(\text{Difference} = P \left( \frac{R}{100} \right)^2\)
Substitute the values:
\(16.80 = P \left( \frac{8}{100} \right)^2\)
\(16.80 = P \left( \frac{2}{25} \right)^2\)
\(16.80 = P \times \frac{4}{625}\)
Now, solve for P:
\(P = 16.80 \times \frac{625}{4}\)
\(P = \frac{16.80 \times 625}{4}\)
We can perform the calculation:
\(16.80 \div 4 = 4.20\)
So,
\(P = 4.20 \times 625\)
Let's calculate \(4.20 \times 625\):
\(4.2 \times 625 = (4 + 0.2) \times 625 = 4 \times 625 + 0.2 \times 625\)
\(4 \times 625 = 2500\)
\(0.2 \times 625 = \frac{1}{5} \times 625 = \frac{625}{5} = 125\)
\(P = 2500 + 125 = 2625\)
Thus, the principal amount is Rs. 2,625.
Let's check this with the calculated difference formula \(\frac{4P}{625}\):
Difference = \(\frac{4 \times 2625}{625}\)
We know \(2625 = 4.20 \times 625\), so let's use that:
Difference = \(\frac{4 \times (4.20 \times 625)}{625} = 4 \times 4.20 = 16.80\)
This matches the given difference, confirming our principal amount calculation is correct.
The principal amount is Rs. 2,625.
| Given Information | Value |
|---|---|
| Difference (CI - SI) | Rs. 16.80 |
| Rate (R) | 8% p.a. |
| Time (T) | 2 years |
| Concept | Description | Formula (for Principal P, Rate R, Time T) |
|---|---|---|
| Simple Interest (SI) | Interest calculated only on the principal amount. | \(\text{SI} = \frac{P \times R \times T}{100}\) |
| Compound Interest (CI) | Interest calculated on the principal amount and also on the accumulated interest from previous periods. | \(\text{CI} = P \left[ \left(1 + \frac{R}{100}\right)^T - 1 \right]\) (compounded annually) |
| Amount (Simple Interest) | Principal + Simple Interest | \(A = P + \text{SI} = P \left(1 + \frac{RT}{100}\right)\) |
| Amount (Compound Interest) | Principal + Compound Interest | \(A = P \left(1 + \frac{R}{100}\right)^T\) (compounded annually) |
| Difference (CI - SI) for 2 Years | The difference in interest earned over 2 years. | \(\text{Difference} = P \left(\frac{R}{100}\right)^2\) (compounded annually) |
| Difference (CI - SI) for 3 Years | The difference in interest earned over 3 years. | \(\text{Difference} = P \left(\frac{R}{100}\right)^2 \left(\frac{300+R}{100}\right)\) (compounded annually) |
Understanding simple interest and compound interest is fundamental in financial mathematics. Simple interest is easier to calculate but earns less over time compared to compound interest, especially over longer periods and at higher rates.
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