This solution explains how to calculate the rate of interest when the amount, principal, and time period (compounded yearly) are given.
The formula for the amount (A) when compounded yearly is:
$ A = P \left(1 + \frac{R}{100}\right)^T $
Where:
From the question, we have:
Since the time period ($T$) is 1 year, the formula simplifies to:
$ A = P \left(1 + \frac{R}{100}\right) $
Substitute the given values into the simplified formula:
$ 600 = 450 \left(1 + \frac{R}{100}\right) $
Now, solve for the rate ($R$):
$ \frac{600}{450} = 1 + \frac{R}{100} $
$ \frac{4}{3} = 1 + \frac{R}{100} $
$ \frac{4}{3} - 1 = \frac{R}{100} $
$ \frac{1}{3} = \frac{R}{100} $
$ R = \frac{1}{3} \times 100 $
$ R = 33.33... \% $
The calculated rate of interest is 33.33%.
A sum of money becomes three times itself in 3 years at compound interest.
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A sum becomes 5 times of itself in 3 years. at compound interest (interest is compounded annually). In how many years. will the sum becomes 125 times of itself?
If the compound interest on a certain sum of money for two years at 9% p.a. is Rs. 3,762, then the sum is: