This problem requires calculating the compound interest (CI) on a given principal amount (P) at a specific annual interest rate (R) for a certain time period (T), with compounding occurring 8-monthly.
Since interest is compounded 8-monthly, we need to adjust the rate and time period accordingly.
The formula for the amount (A) after n periods is:
$A = P \left(1 + \frac{R'}{100}\right)^n$Substitute the adjusted values:
$A = 12500 \left(1 + \frac{10}{100}\right)^3$ $A = 12500 \left(1 + 0.1\right)^3$ $A = 12500 (1.1)^3$ $A = 12500 \times 1.331$ $A = 16637.5$The total amount after 2 years is Rs. 16,637.5.
The compound interest (CI) is the difference between the final amount and the principal amount:
$CI = A - P$ $CI = 16637.5 - 12500$ $CI = 4137.5$Therefore, the compound interest is Rs. 4137.5.
A sum of money becomes three times itself in 3 years at compound interest.
What is the rate of interest?
The certain sum amounts to Rs. 9,982.50 in \(2\frac{1}{2}\) years at 12% p.a., interest compounded 10-monthly. The sum (in Rs.) is:
The difference between the simple interest and the compound interest compounded annually on a certain sum of money for 2 years at a rate of 8% per annum is Rs. 16.80. Find the principle amount.
If a sum of ₹ 2000 is lent at 10% p.a. compound interest, what is the interest for the second year?
A sum becomes 5 times of itself in 3 years. at compound interest (interest is compounded annually). In how many years. will the sum becomes 125 times of itself?
If the compound interest on a certain sum of money for two years at 9% p.a. is Rs. 3,762, then the sum is: