This problem involves calculating the annual rate of compound interest using the amounts at two different time points.
Let the principal sum be 'P' and the annual rate of interest be 'r'. The formula for the amount (A) after 't' years with compound interest compounded annually is:
$ A = P(1 + r)^t $We are given:
Using the formula:
To find the rate 'r', we can divide the second equation by the first equation:
$ \frac{2000}{1600} = \frac{P(1 + r)^3}{P(1 + r)^2} $Simplify the equation:
$ \frac{5}{4} = (1 + r) $Now, solve for 'r':
$ 1 + r = 1.25 $ $ r = 1.25 - 1 $ $ r = 0.25 $Convert the rate to a percentage:
$ \text{Rate} = r \times 100\% = 0.25 \times 100\% = 25\% $Therefore, the rate of interest is 25%.
A sum of money becomes three times itself in 3 years at compound interest.
What is the rate of interest?
The certain sum amounts to Rs. 9,982.50 in \(2\frac{1}{2}\) years at 12% p.a., interest compounded 10-monthly. The sum (in Rs.) is:
The difference between the simple interest and the compound interest compounded annually on a certain sum of money for 2 years at a rate of 8% per annum is Rs. 16.80. Find the principle amount.
If a sum of ₹ 2000 is lent at 10% p.a. compound interest, what is the interest for the second year?
A sum becomes 5 times of itself in 3 years. at compound interest (interest is compounded annually). In how many years. will the sum becomes 125 times of itself?
If the compound interest on a certain sum of money for two years at 9% p.a. is Rs. 3,762, then the sum is: