Evaluating the Decimal Expression
The problem requires calculating the value of the expression:
$ \frac{(0.03)\times(0.05)\times(1.5)}{0.0225} $
Step-by-Step Calculation
-
First, calculate the product of the numbers in the numerator:
$ (0.03) \times (0.05) = 0.0015 $ -
Next, multiply this result by 1.5:
$ 0.0015 \times 1.5 = 0.00225 $So, the numerator evaluates to 0.00225.
-
Now, divide the result from the numerator by the denominator:
$ \frac{0.00225}{0.0225} $ -
To simplify the division, we can multiply both the numerator and the denominator by 100000 to eliminate the decimals:
$ \frac{0.00225 \times 100000}{0.0225 \times 100000} = \frac{225}{2250} $ -
Simplify the fraction:
$ \frac{225}{2250} = \frac{1}{10} $ -
Convert the fraction to its decimal form:
$ \frac{1}{10} = 0.1 $
Therefore, the value of the given expression is 0.1.
Similar Questions
- Solve the following.
$3.142 + 3.61 - 2.12 + 4 - 7.6 =$ ? What will the value of the following be (correct to three decimal points)?
$160.342 - 32.124$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
- Which of the following has terminal decimal representation?
- The value of $0.\overline{23} + 0.\overline{22}$ is:
- If the value of $\frac{1}{36.18}$ is $0.0276$, then what is the value of $\frac{1}{0.0003618}$?
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$- When 0.434343..... is converted into a fraction, then the result will be:
- $0.5\overline{32}$ is equivalent to the fraction:
- How will you write 2.84 hours in hours, minutes and seconds?
Important Questions from Decimals
What is the result when 0.129129129… is converted to a fraction?
Which of the following statement(s) is/are correct?
I. (3/11) > 0.3
II. (7/8) > 0.86
The value of \(1.\overline{3}+0.\overline{69}-0.5\overline{23}\) is equal to:
The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\) is equal to:
If 19 × 23 = 437, then find the value of (190 × 0.023).
