Find the sum of \(\frac{0.01}{0.1}+\frac{0.1}{0.01}\)
10.10
We need to find the sum of the expression: \(\frac{0.01}{0.1}+\frac{0.1}{0.01}\). This involves calculating the value of each fraction and then adding them together.
To evaluate the first term, we can remove the decimals by multiplying both the numerator and the denominator by a power of 10. The highest number of decimal places is two (in 0.01), so we multiply by \(10^2 = 100\).
$$ \frac{0.01}{0.1} = \frac{0.01 \times 100}{0.1 \times 100} = \frac{1}{10} $$
As a decimal, \(\frac{1}{10}\) is equal to \(0.1\).
Similarly, to evaluate the second term, we multiply both the numerator and the denominator by 100 to remove decimals.
$$ \frac{0.1}{0.01} = \frac{0.1 \times 100}{0.01 \times 100} = \frac{10}{1} $$
As a decimal, \(\frac{10}{1}\) is equal to \(10\).
Now we add the values of the two terms we calculated:
$$ \text{Sum} = \text{First Term} + \text{Second Term} $$
$$ \text{Sum} = 0.1 + 10 $$
$$ \text{Sum} = 10.1 $$
The sum is \(10.1\). Looking at the options, \(10.1\) is the same as \(10.10\).
Let's check the calculated sum against the given options:
Our calculated sum, \(10.1\), matches Option 2, which is \(10.10\).
Therefore, the sum of \(\frac{0.01}{0.1}+\frac{0.1}{0.01}\) is \(10.10\).
What is the result when 0.129129129… is converted to a fraction?
Which of the following statement(s) is/are correct?
I. (3/11) > 0.3
II. (7/8) > 0.86
The value of \(1.\overline{3}+0.\overline{69}-0.5\overline{23}\) is equal to:
The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\) is equal to:
If 19 × 23 = 437, then find the value of (190 × 0.023).