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Question

The value of $0.\overline{23} + 0.\overline{22}$ is:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$0.\overline{45}$

Repeating Decimal Addition Explained

This solution explains how to find the sum of two repeating decimals, $0.\overline{23}$ and $0.\overline{22}$.

Convert Repeating Decimals to Fractions

Repeating decimals can be accurately represented as fractions. A repeating decimal of the form $0.\overline{ab}$ is equal to the fraction $\frac{ab}{99}$.

  • Convert $0.\overline{23}$: $0.\overline{23} = \frac{23}{99}$
  • Convert $0.\overline{22}$: $0.\overline{22} = \frac{22}{99}$

Add the Fractions

Now, add the fractional representations:

$ \frac{23}{99} + \frac{22}{99} = \frac{23 + 22}{99} = \frac{45}{99} $

Convert Sum Back to Repeating Decimal

Convert the resulting fraction $\frac{45}{99}$ back into a repeating decimal. Since the denominator is 99, the numerator represents the repeating part.

$ \frac{45}{99} = 0.454545... = 0.\overline{45} $

Therefore, the value of $0.\overline{23} + 0.\overline{22}$ is $0.\overline{45}$.

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Important Questions from Decimals

  1. What is the result when 0.129129129… is converted to a fraction?

  2. Which of the following statement(s) is/are correct?

    I. (3/11) > 0.3

    II. (7/8) > 0.86

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  4. The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\)  is equal to:

  5. If 19 × 23 = 437, then find the value of (190 × 0.023).

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