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Question

The value of $0.\overline{23} + 0.\overline{22}$ is:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$0.\overline{45}$

Repeating Decimal Addition Explained

This solution explains how to find the sum of two repeating decimals, $0.\overline{23}$ and $0.\overline{22}$.

Convert Repeating Decimals to Fractions

Repeating decimals can be accurately represented as fractions. A repeating decimal of the form $0.\overline{ab}$ is equal to the fraction $\frac{ab}{99}$.

  • Convert $0.\overline{23}$: $0.\overline{23} = \frac{23}{99}$
  • Convert $0.\overline{22}$: $0.\overline{22} = \frac{22}{99}$

Add the Fractions

Now, add the fractional representations:

$ \frac{23}{99} + \frac{22}{99} = \frac{23 + 22}{99} = \frac{45}{99} $

Convert Sum Back to Repeating Decimal

Convert the resulting fraction $\frac{45}{99}$ back into a repeating decimal. Since the denominator is 99, the numerator represents the repeating part.

$ \frac{45}{99} = 0.454545... = 0.\overline{45} $

Therefore, the value of $0.\overline{23} + 0.\overline{22}$ is $0.\overline{45}$.

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Important Questions from Decimals

  1. The value of \(\frac{1}{4} + \frac{{[{{(20.35)}^2} - {{(8.35)}^2}] \times 0.0175}}{{{{(1.05)}^2} + (1.05)(27.65)}}\)  is:

  2. The value of \(0.4\overline 6 + 0.7\overline {23} - 0.3\overline 9 \times 0.\overline 7 \)  is:

  3. The value of \(\frac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.55)^2-(5.65)^2]\times19.8} \)  is:

  4. Find the value of (1.6) 3 - (0.9) 3 - (0.7) 3.

  5. What is the value of x, if \(5\left( {1 - \frac{x}{5}} \right) - (5 - x) - \frac{1}{{200}}{\rm{of (20 - x) = 0}}{\rm{.08}}\) ?

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