We are given the value of a reciprocal:
$ \frac{1}{36.18} = 0.0276 $
We need to find the value of $\frac{1}{0.0003618}$.
Let's express the second denominator ($0.0003618$) in terms of the first denominator ($36.18$).
Observe that $0.0003618$ can be written as $36.18 \times 10^{-5}$. This is because moving the decimal point 5 places to the right in $0.0003618$ gives $36.18$.
Therefore, $0.0003618 = \frac{36.18}{10^5}$.
Now substitute this into the expression we need to evaluate:
$ \frac{1}{0.0003618} = \frac{1}{\frac{36.18}{10^5}} $
Using the property of fractions $\frac{1}{a/b} = \frac{b}{a}$, we get:
$ \frac{10^5}{36.18} $
This can be rewritten as:
$ 10^5 \times \frac{1}{36.18} $
We know that $\frac{1}{36.18} = 0.0276$. Substitute this value:
$ 10^5 \times 0.0276 $
Calculate the final value:
$ 100000 \times 0.0276 = 2760 $
The value of $\frac{1}{0.0003618}$ is 2760.
What will the value of the following be (correct to three decimal points)?
$160.342 - 32.124$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$
What is the result when 0.129129129… is converted to a fraction?
Which of the following statement(s) is/are correct?
I. (3/11) > 0.3
II. (7/8) > 0.86
The value of \(1.\overline{3}+0.\overline{69}-0.5\overline{23}\) is equal to:
The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\) is equal to:
If 19 × 23 = 437, then find the value of (190 × 0.023).