$\frac{51}{90}$
This solution explains the process of converting a repeating decimal into its equivalent fraction using algebraic methods. It focuses on demonstrating the calculation relevant to the provided answer options.
Represent the repeating decimal with a variable. Based on the structure of the options provided, we will demonstrate the conversion for the decimal $0.5\overline{6}$, which represents $0.5666...$
Let $y = 0.5\overline{6}$.
To work with the repeating part, set up algebraic equations. Multiply $y$ by 10 to shift the decimal point just before the repeating sequence begins:
$10y = 5.666...$
Multiply $y$ by 100 (which is $10 \times 10$) to shift the decimal point just after the first cycle of the repeating digits:
$100y = 56.666...$
Subtract the equation from Step 2 ($10y$) from the equation in Step 3 ($100y$). This step eliminates the infinitely repeating part of the decimal:
$100y = 56.666...$
$- \quad 10y = \quad 5.666...$
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$90y = 51.000...$
This simplifies to $90y = 51$.
Solve for $y$ by dividing both sides of the equation by 90:
$y = \frac{51}{90}$
The resulting fraction is $\frac{51}{90}$. This fraction matches one of the provided options, confirming the conversion process.
What will the value of the following be (correct to three decimal points)?
$160.342 - 32.124$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$
What is the result when 0.129129129… is converted to a fraction?
Which of the following statement(s) is/are correct?
I. (3/11) > 0.3
II. (7/8) > 0.86
The value of \(1.\overline{3}+0.\overline{69}-0.5\overline{23}\) is equal to:
The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\) is equal to:
If 19 × 23 = 437, then find the value of (190 × 0.023).