$\frac{51}{90}$
This solution explains the process of converting a repeating decimal into its equivalent fraction using algebraic methods. It focuses on demonstrating the calculation relevant to the provided answer options.
Represent the repeating decimal with a variable. Based on the structure of the options provided, we will demonstrate the conversion for the decimal $0.5\overline{6}$, which represents $0.5666...$
Let $y = 0.5\overline{6}$.
To work with the repeating part, set up algebraic equations. Multiply $y$ by 10 to shift the decimal point just before the repeating sequence begins:
$10y = 5.666...$
Multiply $y$ by 100 (which is $10 \times 10$) to shift the decimal point just after the first cycle of the repeating digits:
$100y = 56.666...$
Subtract the equation from Step 2 ($10y$) from the equation in Step 3 ($100y$). This step eliminates the infinitely repeating part of the decimal:
$100y = 56.666...$
$- \quad 10y = \quad 5.666...$
--------------------
$90y = 51.000...$
This simplifies to $90y = 51$.
Solve for $y$ by dividing both sides of the equation by 90:
$y = \frac{51}{90}$
The resulting fraction is $\frac{51}{90}$. This fraction matches one of the provided options, confirming the conversion process.
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
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The value of \(0.4\overline 6 + 0.7\overline {23} - 0.3\overline 9 \times 0.\overline 7 \) is:
The value of \(\frac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.55)^2-(5.65)^2]\times19.8} \) is:
Find the value of (1.6) 3 - (0.9) 3 - (0.7) 3.
What is the value of x, if \(5\left( {1 - \frac{x}{5}} \right) - (5 - x) - \frac{1}{{200}}{\rm{of (20 - x) = 0}}{\rm{.08}}\) ?