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Question

What is the sum of the first 12 multiples of 4?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
312

Identifying the Sequence of Multiples

The question asks for the sum of the first 12 multiples of 4. These multiples form a sequence:

  • 4 x 1 = 4
  • 4 x 2 = 8
  • 4 x 3 = 12
  • ...
  • 4 x 12 = 48

This sequence is an arithmetic progression (AP) where:

  • The first term ($a$) is 4.
  • The common difference ($d$) is 4.
  • The number of terms ($n$) is 12.
  • The last term ($l$) is 48.

Calculating the Sum using AP Formula

The sum ($S_n$) of an arithmetic progression can be calculated using the formula:

$ S_n = \frac{n}{2}(a + l) $

Substitute the values:

$ S_{12} = \frac{12}{2}(4 + 48) $

$ S_{12} = 6 \times 52 $

$ S_{12} = 312 $

Alternatively, using the formula $S_n = \frac{n}{2}(2a + (n-1)d)$:

$ S_{12} = \frac{12}{2}(2 \times 4 + (12-1) \times 4) $

$ S_{12} = 6(8 + 11 \times 4) $

$ S_{12} = 6(8 + 44) $

$ S_{12} = 6 \times 52 $

$ S_{12} = 312 $

Final Answer

The sum of the first 12 multiples of 4 is 312.

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  2. If the sum of five consecutive multiples of 2 is 660, then find the largest number.
  3. The $10^{\text{th}}$ term of the Arithmetic Progression $2, 7, 12, \dots$ is:
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Important Questions from Arithmetic Progression

  1. If the nth term of a sequence is \(\frac{2 n+5}{7}\), then what is the sum of its first 140 terms? 

  2. What is the arithmetic mean of first 8 multiples of 13?

  3. The average of five consecutive odd natural numbers is 27. The product of the first and fifth number is:

  4. Find the sum of all the numbers between 100 to 200 which are divisible by 12.

  5. In a garden, there are 6 daisy plants the first year. Each year, a gardener adds 3 new daisy plants the first year and loses 2 each year. He has 26 jasmine plants the first year and loses 2 each year. When will the number of daisy plants equal the number of jasmine plants after the first year?

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