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Question

If the sum of five consecutive multiples of 2 is 660, then find the largest number.

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
136

Problem Breakdown: Consecutive Multiples of 2

We are asked to find the largest of five consecutive multiples of 2, given that their sum is 660.

Setting Up the Algebraic Equation

Let the five consecutive multiples of 2 be represented algebraically. If we denote the middle multiple as x, the sequence can be written as:

  • x - 4
  • x - 2
  • x
  • x + 2
  • x + 4

The sum of these five consecutive multiples is given as 660. We can write this as an equation:

$ (x - 4) + (x - 2) + x + (x + 2) + (x + 4) = 660 $

Solving for the Middle Multiple

Simplify the equation by combining like terms:

$ 5x = 660 $

Now, solve for x by dividing both sides by 5:

$ x = \frac{660}{5} $

$ x = 132 $

So, the middle multiple of 2 is 132.

Finding the Largest Multiple

The five consecutive multiples are:

  • 132 - 4 = 128
  • 132 - 2 = 130
  • 132
  • 132 + 2 = 134
  • 132 + 4 = 136

The largest number in this sequence is x + 4.

$ \text{Largest Number} = 132 + 4 = 136 $

The largest number among the five consecutive multiples of 2 is 136.

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