We are asked to find the largest of five consecutive multiples of 2, given that their sum is 660.
Let the five consecutive multiples of 2 be represented algebraically. If we denote the middle multiple as x, the sequence can be written as:
The sum of these five consecutive multiples is given as 660. We can write this as an equation:
$ (x - 4) + (x - 2) + x + (x + 2) + (x + 4) = 660 $
Simplify the equation by combining like terms:
$ 5x = 660 $
Now, solve for x by dividing both sides by 5:
$ x = \frac{660}{5} $
$ x = 132 $
So, the middle multiple of 2 is 132.
The five consecutive multiples are:
The largest number in this sequence is x + 4.
$ \text{Largest Number} = 132 + 4 = 136 $
The largest number among the five consecutive multiples of 2 is 136.
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