The problem asks for the 10th term of a given Arithmetic Progression (AP).
The formula for the $n^{\text{th}}$ term of an Arithmetic Progression is:
$a_n = a + (n-1)d$
Substitute the known values into the formula:
Calculate the 10th term ($a_{10}$):
$a_{10} = 2 + (10-1) \times 5$
$a_{10} = 2 + (9) \times 5$
$a_{10} = 2 + 45$
$a_{10} = 47$
The 10th term of the Arithmetic Progression is 47.
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