The problem asks for the 10th term of the sequence 2, 5, 8, 11, ....
This sequence is an Arithmetic Progression (AP) because the difference between consecutive terms is constant.
The formula to find the $n$-th term ($a_n$) of an AP is:
$ a_n = a + (n-1)d $Where:
We need to find the 10th term, so $n=10$. Plugging the values into the formula:
$ a_{10} = 2 + (10-1) \times 3 $
$ a_{10} = 2 + (9) \times 3 $
$ a_{10} = 2 + 27 $
$ a_{10} = 29 $
The tenth term of the sequence is 29.
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