Calculating HCF of 28 and 49
First, find the Highest Common Factor (HCF) of 28 and 49.
- Prime factorization of 28: $2 \times 2 \times 7 = 2^2 \times 7^1$
- Prime factorization of 49: $7 \times 7 = 7^2$
- The common factor is 7.
Therefore, the HCF(28, 49) = 7.
Calculating LCM of 28 and 49
Next, find the Least Common Multiple (LCM) of 28 and 49.
- Using the prime factorizations: $2^2$ and $7^2$.
- LCM is the product of the highest powers of all prime factors involved.
- LCM(28, 49) = $2^2 \times 7^2$
- LCM(28, 49) = $4 \times 49$
Therefore, the LCM(28, 49) = 196.
Finding the Sum of HCF and LCM
Finally, calculate the sum of the HCF and LCM.
- Sum = HCF + LCM
- Sum = 7 + 196
- Sum = 203
The sum of the HCF and LCM of 28 and 49 is 203.
Similar Questions
- The H.C.F. and the L.C.M. of two numbers are 5 and 495, respectively. If one of the numbers is 55, find the other one.
- The HCF of two numbers is 16 and their LCM is 240. If one number is 48, find the other number.
- The sum of two numbers is 132 and their L.C.M. is 630. What are the two numbers?
- The LCM of the numbers 12.8 and 0.004 is:
- Find the least number which is divisible by first ten natural numbers.
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- HCF of $\frac{1}{3}, \frac{3}{4}, \frac{4}{5}$ and $\frac{5}{6}$ is:
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- If the LCM of $20x^3y^2$ and $10x^4y^4$ is $20x^4y^4$, find the HCF.
Important Questions from LCM and HCF
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?
