A 4-digit number is selected at random formed by using the digits 0, 1, 2, 3 and 4 (where repetition of digits is not allowed).
We need to find the probability that a randomly selected 4-digit number, formed using the digits 0, 1, 2, 3, 4 without repetition, is divisible by 4.
A 4-digit number cannot start with 0. The digits are {0, 1, 2, 3, 4} without repetition.
The total number of possible 4-digit numbers is calculated as: \( 4 \times 4 \times 3 \times 2 = 96 \) There are 96 possible 4-digit numbers.
A number is divisible by 4 if its last two digits form a number divisible by 4. We list the possible pairs of last two digits (XY) using {0, 1, 2, 3, 4} without repetition:
The total number of favorable outcomes (numbers divisible by 4) is the sum of ways for each ending:
6 + 4 + 6 + 4 + 4 + 6 = 30 There are 30 numbers divisible by 4.The probability is the ratio of favorable outcomes to total possible outcomes:
\( P(\text{Number is divisible by 4}) = \frac{\text{Total numbers divisible by 4}}{\text{Total possible 4-digit numbers}} \) \( P = \frac{30}{96} \)Simplifying the fraction:
\( P = \frac{30 \div 6}{96 \div 6} = \frac{5}{16} \)The probability is 5/16.
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