All Exams Test series for 1 year @ ₹349 only
Question

For the next five (05) items that follow :
A 4-digit number is selected at random formed by using the digits 0, 1, 2, 3 and 4 (where repetition of digits is not allowed).

What is the probability that the number selected is divisible by 4 ?

This question was previously asked in
NDA 2 2026 GAT Question Paper (13-Sep-2026)
The correct answer is
5/16

We need to find the probability that a randomly selected 4-digit number, formed using the digits 0, 1, 2, 3, 4 without repetition, is divisible by 4.

Calculating Total Possible Numbers

A 4-digit number cannot start with 0. The digits are {0, 1, 2, 3, 4} without repetition.

  • First digit: 4 choices (cannot be 0, so 1, 2, 3, 4).
  • Second digit: 4 choices (remaining digits including 0).
  • Third digit: 3 choices.
  • Fourth digit: 2 choices.

The total number of possible 4-digit numbers is calculated as: \( 4 \times 4 \times 3 \times 2 = 96 \) There are 96 possible 4-digit numbers.

Calculating Favorable Outcomes (Divisible by 4)

A number is divisible by 4 if its last two digits form a number divisible by 4. We list the possible pairs of last two digits (XY) using {0, 1, 2, 3, 4} without repetition:

  • Ending in 04: Digits used {0, 4}. Remaining {1, 2, 3}. First digit has 3 choices, second has 2. Ways = \(3 \times 2 = 6\).
  • Ending in 12: Digits used {1, 2}. Remaining {0, 3, 4}. First digit has 2 choices (not 0). Second digit has 2 choices. Ways = \(2 \times 2 = 4\).
  • Ending in 20: Digits used {2, 0}. Remaining {1, 3, 4}. First digit has 3 choices. Second digit has 2. Ways = \(3 \times 2 = 6\).
  • Ending in 24: Digits used {2, 4}. Remaining {0, 1, 3}. First digit has 2 choices (not 0). Second digit has 2 choices. Ways = \(2 \times 2 = 4\).
  • Ending in 32: Digits used {3, 2}. Remaining {0, 1, 4}. First digit has 2 choices (not 0). Second digit has 2 choices. Ways = \(2 \times 2 = 4\).
  • Ending in 40: Digits used {4, 0}. Remaining {1, 2, 3}. First digit has 3 choices. Second digit has 2. Ways = \(3 \times 2 = 6\).

The total number of favorable outcomes (numbers divisible by 4) is the sum of ways for each ending:

6 + 4 + 6 + 4 + 4 + 6 = 30 There are 30 numbers divisible by 4.

Calculating the Probability

The probability is the ratio of favorable outcomes to total possible outcomes:

\( P(\text{Number is divisible by 4}) = \frac{\text{Total numbers divisible by 4}}{\text{Total possible 4-digit numbers}} \) \( P = \frac{30}{96} \)

Simplifying the fraction:

\( P = \frac{30 \div 6}{96 \div 6} = \frac{5}{16} \)

The probability is 5/16.

Was this answer helpful?

Similar Questions

  1. An edible oil is sold at the rates 150, 200, 250, 300 rupees per litre in four consecutive years. Assuming that an equal amount of money is spent on oil by a family in every year during these years, what is the average price of oil in rupees (approximately) per litre ?
  2. Let \(m = 77^n\). The index \(n\) is given a positive integral value at random. What is the probability that the value of \(m\) will have 1 in the units place ?
  3. What is \(P(A) + P(B) + P(C)\) equal to ?
  4. A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If \(3P(B) = 4P(A)\) and \(3P(C) = 2P(B)\), then what is \(P(A)\) equal to?
  5. A die has two faces with number 4, three faces with number 5 and one face with number 6. If the die is rolled once, then what is the probability of getting 4 or 5?
  6. A box contains 2 black, 4 yellow and 6 white balls. Three balls are drawn in succession with replacement. What is the probability that all three are of the same colour?
  7. The letters of the word ZOOLOGY are arranged in all possible ways. What is the probability that the consonants and vowels occur alternatively?
  8. A natural number \(x\) is chosen at random from the first 100 natural numbers. What is the probability that \(x^2 + x > 50\)?
  9. A fair coin is tossed till two heads occur in succession. What is the probability that the number of tosses required is less than 6?
  10. Two perfect dice are thrown. What is the probability that the sum of the numbers on the faces is neither 9 nor 10?

Important Questions from Probability

  1. The probability of being 53 Sundays in year 2020 is-

  2. Three dice are thrown randomly. The probability of coming 3 in at least one die is

  3. The probability of having 53 Tuesdays in an ordinary year is:

  4. Two dice are thrown simultaneously The probability of getting the sum 2 or 8 or 12 is

  5. If two balanced dice are tossed once, the probability of the event, that the sum of the integers coming on the upper sides of the two dice is 9, is

Need Expert Advice?
Test Series
NDA img
Defence
NDA 2026 Mock Test Series (Latest Pattern)
503 Tests 1 Tests Free
1148 Attempts
4.7(142)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App