To find the probability that the total of the numbers on the dice is at least 23 when four dice are rolled, we need to follow these steps:

• Each standard six-faced die has numbers from 1 to 6. Therefore, the minimum sum on four dice is 4 (1 on each die) and the maximum sum is 24 (6 on each die).
• We are concerned with the sums of 23 and 24, as these are the only sums that are "at least 23".

Now, let's calculate the total number of possible outcomes when four dice are rolled:

• Each die has 6 faces, so for four dice, total outcomes are \(6^4\).
• Calculating this, we have \(6 \times 6 \times 6 \times 6 = 1296\).

Next, we calculate the favorable outcomes for sums 23 and 24:

• To get a sum of 24: Each die must show a 6. This is only one possible outcome: (6, 6, 6, 6).
• To get a sum of 23: Three dice must show 6, and one die must show 5. This can happen in 4 ways: (6, 6, 6, 5), (6, 6, 5, 6), (6, 5, 6, 6), (5, 6, 6, 6).
• Therefore, there are 4 ways to roll a sum of 23.

Adding the number of outcomes for getting sums 23 and 24 gives us 5 favorable outcomes:

• 1 outcome for a sum of 24 and 4 outcomes for a sum of 23.

Finally, the probability is calculated as the number of favorable outcomes divided by the total number of outcomes:

• Probability = \(\frac{5}{1296}\).

Thus, the probability that the sum is at least 23 is \(\frac{5}{1296}\), which matches the given correct answer.