Probability Calculation for a Special Die
This problem asks for the probability of a specific event occurring when rolling a non-standard die. We need to determine the chances of rolling either a 4 or a 5.
Understanding the Die Properties
First, let's list the properties of the die as described:
- The die has a total of 6 faces (standard for a die).
- Number of faces showing '4': 2
- Number of faces showing '5': 3
- Number of faces showing '6': 1
We can represent this information in a table:
| Number on Face | Number of Faces |
|---|---|
| 4 | 2 |
| 5 | 3 |
| 6 | 1 |
| Total | 6 |
Identifying Favorable Outcomes
The event we are interested in is rolling a 4 OR a 5. The number of faces that satisfy this condition (favorable outcomes) is the sum of faces showing 4 and faces showing 5.
- Number of faces with '4' = 2
- Number of faces with '5' = 3
- Total favorable outcomes = Number of faces with '4' + Number of faces with '5' = 2 + 3 = 5
Calculating the Probability
Probability is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes.
The formula for probability is:
\( P(\text{Event}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \)
In this case:
- Number of Favorable Outcomes (getting a 4 or 5) = 5
- Total Number of Possible Outcomes (total faces) = 6
Therefore, the probability of rolling a 4 or 5 is:
\( P(\text{4 or 5}) = \frac{5}{6} \)
So, the probability of getting a 4 or 5 when this die is rolled once is \(\frac{5}{6}\).
Similar Questions
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Important Questions from Probability
Two dice are thrown simultaneously. What is the probability of getting the same number on both the dice?
The probability of being 53 Sundays in year 2020 is-
Three dice are thrown randomly. The probability of coming 3 in at least one die is
The probability of having 53 Tuesdays in an ordinary year is:
When two dice are tossed simultaneously, the probability that the sum of the numbers appearing on both the dice is 8 will be
