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Question

The probability that a family owns a laptop is 0.68; that it also owns a desktop is 0.56. If the probability that it owns both is 0.48, then what is the probability that a randomly selected family owns a laptop or a desktop?

This question was previously asked in
NDA 2 2025 GAT Question Paper (14-Sep-2025)
The correct answer is

0.76 

To solve the problem, we need to use the principle of inclusion-exclusion to find the probability that a family owns either a laptop or a desktop.

Let:

  • \(P(L)\) be the probability that a family owns a laptop = 0.68
  • \(P(D)\) be the probability that a family owns a desktop = 0.56
  • \(P(L \cap D)\) be the probability that a family owns both a laptop and a desktop = 0.48

 

We are required to find the probability that a family owns a laptop or a desktop. This is denoted by \(P(L \cup D)\), and the formula for this probability is:

\(P(L \cup D) = P(L) + P(D) - P(L \cap D)\)

Now, substituting the given values into the formula:

\(P(L \cup D) = 0.68 + 0.56 - 0.48\)

Simplifying this expression:

\(P(L \cup D) = 1.24 - 0.48 = 0.76\)

Therefore, the probability that a randomly selected family owns either a laptop or a desktop is 0.76.

Conclusion: The correct answer is 0.76, which corresponds to the first option.

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    2. 1 ball selected at random from the bag.

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    II. The probability that a red ball is selected is 6/15

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    B. Only conclusion II follows.

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