Question
What is the cube root of 1728?
This question was previously asked in
UPTET 2026 Paper 2 Social Studies Question Paper (3-Jul-2026) (Shift 1)
The correct answer is
12
To find the cube root of 1728, express it as a product of prime factors: \(1728 = 2^6 \times 3^3\).
So, \(\sqrt[3]{1728} = \sqrt[3]{2^6 \times 3^3} = 2^2 \times 3 = 4 \times 3 = 12\).
Verification: \(12^3 = 12 \times 12 \times 12 = 1728\).
Was this answer helpful?
Similar Questions
Simplify the following expression:
\[ \left(\frac{x^2}{x^m}\right)^{1+m} \left(\frac{x^m}{x^n}\right)^{m+n} \left(\frac{x^n}{x^l}\right)^{n+l} \]
If 2ˣ = 4ˣ⁻¹, find x.
Evaluate √(19 - 6√10) + 3
If 27(x/3) = 9, find x.
Important Questions from Surds and Indices
The cube root of - 64 × - 1331 is:
If (27) m = (81) n, then m 2: mn = ?
if 49 n + 49 n + 49 n + 49 n + 49 n + 49 n + 49 n = 7 2221 , then n = ?
If a x= b y= c zand b 2= ac then y =
The value of (0.3) [{(200 - 146)/(3 × 3 × 3)} - 3] is:
Need Expert Advice?
Upcoming Exams
CTET
December 12, 2026
Test Series
Teaching
UPTET 2026 (Paper 1 & 2) Mock Test Series
257 Tests 16 Tests Free
2166 Attempts
4.6(18)
English, Hindi
More Questions from UP TET
