Find the cube root of 78402752
428
The question asks us to find the cube root of the number 78402752. Finding the cube root means finding a number that, when multiplied by itself three times, equals 78402752. We can write this mathematically as finding \(x\) such that \(x^3 = 78402752\), or \(x = \sqrt[3]{78402752}\).
We can use a method involving the unit digit and estimation to solve this problem efficiently, especially when dealing with perfect cubes and multiple-choice options.
The unit digit of the number 78402752 is 2. We need to find which digit, when cubed, results in a number with a unit digit of 2. Let's look at the cubes of single digits:
From the list above, we can see that only the digit 8, when cubed (\(8^3 = 512\)), results in a number with a unit digit of 2. Therefore, the unit digit of the cube root of 78402752 must be 8.
Let's look at the given options and check their unit digits:
Based on our analysis in Step 1, the unit digit of the correct cube root must be 8. Out of the given options, only 428 has a unit digit of 8.
Since only one option, 428, matches the required unit digit, it is highly likely to be the correct answer. To confirm, let's calculate the cube of 428:
\(428^3 = 428 \times 428 \times 428\)
First, calculate \(428 \times 428\):
| 4 | 2 | 8 | |||||
|---|---|---|---|---|---|---|---|
| × | 4 | 2 | 8 | ||||
| 3 | 4 | 2 | 4 | (428 × 8) | |||
| 8 | 5 | 6 | (428 × 20) | ||||
| 1 | 7 | 1 | 2 | (428 × 400) | |||
| 1 | 8 | 3 | 1 | 8 | 4 | (Sum) | |
\(428 \times 428 = 183184\)
Now, calculate \(183184 \times 428\):
| 1 | 8 | 3 | 1 | 8 | 4 | ||||
|---|---|---|---|---|---|---|---|---|---|
| × | 4 | 2 | 8 | ||||||
| 1 | 4 | 6 | 5 | 4 | 7 | 2 | (183184 × 8) | ||
| 3 | 6 | 6 | 3 | 6 | 8 | (183184 × 20) | |||
| 7 | 3 | 2 | 7 | 3 | 6 | (183184 × 400) | |||
| 7 | 8 | 4 | 0 | 2 | 7 | 5 | 2 | (Sum) | |
\(428 \times 428 \times 428 = 78402752\)
The result matches the original number. Therefore, the cube root of 78402752 is indeed 428.
Using the unit digit method was a quick way to narrow down the options. Verifying the identified option confirms that 428 is the correct cube root of 78402752.
\(\sqrt[3]{78402752} = 428\)
What is the least number which, when multiplied by 28, forms a perfect square?
Find the value of :
[(3 × 3 × 3 × 3 × 3 × 3) 6 ÷ (3 × 3 × 3 × 3) 7 × 3 4]
The cube root of - 64 × - 1331 is:
If \(\sqrt{4624}=68\) , then the value of:
\(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)
If (27) m = (81) n, then m 2: mn = ?