If 27(x/3) = 9, find x.
2
Writing both sides with base 3: \(27^{x/3} = (3^3)^{x/3} = 3^{x}\) and \(9 = 3^2\).
So the equation becomes \(3^{x} = 3^{2}\).
Equating the exponents: \(x = 2\).
The value of x is 2.
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