Direction : Study the following table and answer the questions that follow : Number of visitors and visitors who purchased membership at five fitness centres during a promotional monthFitness Centre Visitors Visitors who purchased membership A 600 240 B 750 375 C 900 540 D 800 400 E 950 570 Total 4000 2125
What fraction of the total visitors who purchased a membership across all five centres was accounted for by Centres C and E together ?
\( \frac{222}{425} \)
Total visitors who purchased membership at all five centres = 2125.
Purchasers at C and E = \( 540 + 570 = 1110 \)
Fraction = \( \frac{1110}{2125} = \frac{222}{425} \) (dividing numerator and denominator by 5).
Check: \( 222 \times 5 = 1110 \) and \( 425 \times 5 = 2125 \); 222 and 425 have no common factor.
Hence, \( \frac{222}{425} \).
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Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |
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