Two trains of equal lengths cross a stationary pole in 12 seconds and 16 seconds, respectively. How long will it take for the trains to cross each other when running in opposite directions? (Write your answer rounded off to two decimal places.)
13.71 seconds
Since both trains have the same length L, their speeds are \(\tfrac{L}{12}\) and \(\tfrac{L}{16}\).
Crossing time in opposite directions: \(\dfrac{2L}{L/12+L/16} = \dfrac{2}{1/12+1/16}\).
\(\dfrac1{12}+\dfrac1{16} = \dfrac{4}{48}+\dfrac{3}{48} = \dfrac{7}{48}\), so time \(=\dfrac{2}{7/48} = \dfrac{96}{7} \approx 13.71\).
Hence, the trains take approximately 13.71 seconds to cross each other.
The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?
The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?
A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is:
A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?
A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?